### 파이썬 14 ~ 20번 틀림

하드코딩 했는데
왜 틀렸는지 모르겠어요
14~20번 중에 16번만 맞고 다 틀립니다.
테스트 케이스 더 주실 수 있나요?

###### 작성중인 코드―solution.py
``````1
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def solution(numbers, hand):
LL = 10
RL = 11
for i in numbers:
if i in [1,4,7]:
LL = i
continue
if i in [3,6,9]:
RL = i
continue

if i==2:
# 4/3
if LL == 10 and RL in [3,5,6,8,9,0]:
RL = i
continue
if RL == 11 and LL in [1,4,5,7,8,0]:
LL = i
continue
# 3 / 2 이하
if LL in [0,7] and RL in [3,5,6,8]:
RL = i
continue
if RL in [0,9] and LL in [1,4,5,8]:
LL = i
continue
# 2 / 1 이하
if LL in [4,8] and RL in [3,5]:
RL = i
continue
if RL in [6,8] and LL in [1,5]:
LL = i
continue
# 0/0 같은 키 누르기
if LL == 2:
continue
if RL == 2:
continue

# 거리가 같은 경우
# 1/1
if LL in [1,5] and RL in [3,5] and hand=="right":
RL = i
continue
if LL in [1,5] and RL in [3,5] and hand=="left":
LL = i
continue
# 2/2
if LL in [4,8] and RL in [6,8] and hand=="right":
RL = i
continue
if LL in [4,8] and RL in [6,8] and hand=="left":
LL= i
continue
# 3/3
if LL in [7,0] and RL in [0,9] and hand=="right":
RL=i
continue
if LL in [7,0] and RL in [0,9] and hand=="left":
LL=i
continue
# 4/4
if LL == 10 and RL == 11 and hand=="left" :
LL = i
continue
if LL == 10 and RL == 11 and hand=="right" :
RL = i
continue

if i==5:
# 3/3
if LL == 10 and RL == 11 and hand=="left" :
LL = i
continue
if LL == 10 and RL == 11 and hand=="right" :
RL = i
continue
# 3/2
if LL == 10 and RL in [2,3,6,8,9,0]:
RL = i
continue
if RL == 11 and LL in [1,2,4,7,8,0]:
LL = i
continue
# 2/1
if LL in [1,7,0] and RL in [2,6,8]:
RL = i
continue
if RL in [3,9,0] and LL in [2,4,8]:
LL = i
continue
# 0/0 같은 키 누르기
if LL == 5:
continue
if RL == 5:
continue

# 거리가 같은 경우
# 1/1
if LL in [2,4,8] and RL in [2,6,8] and hand=="right":
RL = i
continue
if LL in [2,4,8] and RL in [2,6,8] and hand=="left":
LL=i
continue
# 2/2
if LL in [1,7,0] and RL in [3,9,0] and hand=="right":
RL=i
continue
if LL in [1,7,0] and RL in [3,9,0] and hand=="left":
LL=i
continue
# 3/3
if LL == 10 and RL == 11 and hand=="right":
RL=i
continue
if LL == 10 and RL == 11 and hand=="left":
LL=i
continue

if i==8:
# 거리가 다른 경우
# 3 / 2
if LL == 1 and RL in [2,3,5,6,9,0,11]:
RL = i
continue
if RL == 3 and LL in [1,2,4,7,0,10]:
LL = i
continue
# 2 / 1 이하
if LL in [1,2,4,10] and RL in [5,9,0]:
RL = i
continue
if RL in [2,3,6,11] and LL in [5,7,0]:
LL = i
continue
# 1 / 1 같은 키 누르기
if LL == 8:
continue
if RL == 8:
continue

# 거리가 같은 경우
# 왼손거리 1 / 오른손거리 1
if LL in [5,7,0] and RL in [5,9,0] and hand=="right":
RL = i
continue
if LL in [5,7,0] and RL in [5,9,0] and hand=="left":
LL = i
continue

# 왼손거리 2 / 오른손거리 2
if LL in [1,2,4,10] and RL in [2,3,6,11] and hand=="right":
RL = i
continue
if LL in [1,2,4,10] and RL in [2,3,6,11] and hand=="left":
LL = i
continue
# 3 / 3
if LL == 1 and RL == 3 and hand=="right":
RL = i
continue
if LL == 1 and RL == 3 and hand=="left":
LL = i
continue

if i==0:
# 4 / 3
if LL == 1 and RL in [2,5,6,8,9,11]:
RL = i
continue
if RL == 3 and LL in [2,4,5,7,8,10]:
LL = i
continue
# 3 / 2
if LL in [2,4] and RL in [5,6,8,9,11]:
RL = i
continue
if RL in [2,6] and LL in [4,5,7,8,10]:
LL = i
continue
# 2 / 1 이하
if LL in [5,7] and RL in [8,11]:
RL = i
continue
if RL in [5,9] and LL in [8,10]:
LL = i
continue
# 0 / 0 같은 키 누르기
if LL == 0:
continue
if RL == 0:
continue

# 거리가 같은 경우
# 왼손거리 1 / 오른손거리 1
if LL in [8,10] and RL in [8,11] and hand=="right":
RL = i
continue
if LL in [8,10] and RL in [8,11] and hand=="left":
LL = i
continue
# 왼손거리 2 / 오른손거리 2
if LL in [5,7] and RL in [5,9] and hand=="right":
RL = i
continue
if LL in [5,7] and RL in [5,9] and hand=="left":
LL = i
continue
# 왼손거리 3 / 오른손거리 3
if LL in [2,4] and RL in [2,6] and hand=="right":
RL = i
continue
if LL in [2,4] and RL in [2,6] and hand=="left":
LL = i
continue
# 4/4
if LL == 1 and RL == 3 and hand=="right":
RL = i
continue
if LL == 1 and RL == 3 and hand=="left":
LL = i
continue